30 choose 13 is all possible arrangements given a win. Ok.Blitzfrog wrote:
Blitzmeth
Still wrapping my head around the multiplication by 12. A potential error in my method is that my math is a solution for where there are 6 tiles in one constant position for any possible win cases.
The following made realize a definite mistake I let happen:
Now that I think about it, it's a bit more complicated than that. You need to subtract 36 choose 19 by the number of scenarios prohibited due to a 2nd and 3rd six in a row.