it's (√2+ √3)^100 so we should find integer first
(√2+ √3)^8 is 9602. so (√2+ √3)^8 's digit is 2.
and 2^x 's digit goes 2, 4, 8, 6, 2, 4, 8, 6 .....
so (√2+ √3)^96 is 6.
and (√2+ √3)^4 is 97.9897....
(√2+ √3)^96 = 6
6[(√2+ √3)^96's digit] * 97. 9897[(√2+ √3)^4] goes 587, 8382....
so digit is 7
Answer : 7
(√2+ √3)^8 is 9602. so (√2+ √3)^8 's digit is 2.
and 2^x 's digit goes 2, 4, 8, 6, 2, 4, 8, 6 .....
so (√2+ √3)^96 is 6.
and (√2+ √3)^4 is 97.9897....
(√2+ √3)^96 = 6
6[(√2+ √3)^96's digit] * 97. 9897[(√2+ √3)^4] goes 587, 8382....
so digit is 7
Answer : 7