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Scorpiour's Modding Queue (Modding Team)
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which diff?
Another o3o/vahn10 wrote:
which diff?
maybe [Another], i see at #modhelp.
Topic Starter
And also here's an extra ticket for who finds out the correct answer of the following question:
hint: For example, the unit digit of 13.14159 is 3 <-- (the last digit of integer part)
Find the unit digit of 
ps : a simple demonstrate of solution is required if you provide a correct answer
ps : a simple demonstrate of solution is required if you provide a correct answer
hint: For example, the unit digit of 13.14159 is 3 <-- (the last digit of integer part)
9
42
8
错了/.\
(sqrt(2)+sqrt(3))^2=9.898979...
(sqrt(2)+sqrt(3))^4=97.989795...(8)
(sqrt(2)+sqrt(3))^8=9601.999896...
(sqrt(2)+sqrt(3))^16=92198401.999999989..
(sqrt(2)+sqrt(3))^32<...4
(sqrt(2)+sqrt(3))^64<...6
so (sqrt(2)+sqrt(3))^100<(sqrt(2)+sqrt(3))^64*(sqrt(2)+sqrt(3))^32*(sqrt(2)+sqrt(3))^4=………………8*4*6=2
so the unit digit is 1
(sqrt(2)+sqrt(3))^4=97.989795...(8)
(sqrt(2)+sqrt(3))^8=9601.999896...
(sqrt(2)+sqrt(3))^16=92198401.999999989..
(sqrt(2)+sqrt(3))^32<...4
(sqrt(2)+sqrt(3))^64<...6
so (sqrt(2)+sqrt(3))^100<(sqrt(2)+sqrt(3))^64*(sqrt(2)+sqrt(3))^32*(sqrt(2)+sqrt(3))^4=………………8*4*6=2
so the unit digit is 1
3
314
101
lol random guessing
lol random guessing
再试试= =
原式=(√2+√3)^100-(2-√3)^100整数部分等于（√2+√3+√2-√3）^50 (√2+√3-√2+√3)^50
8^25*12^25
8^25 个位是8
2^25 个位2
结果6
原式=(√2+√3)^100-(2-√3)^100整数部分等于（√2+√3+√2-√3）^50 (√2+√3-√2+√3)^50
8^25*12^25
8^25 个位是8
2^25 个位2
结果6
5
Edit: I mistyped >.<
Edit2:Sorry for edits
Edit:3+4
Why:
Edit6:(sqrt(2)+sqrt(3))^100= 60189565958534864248505242941893634932281257785715.1875721641483405
The units digit, is the number before the comma, thus being 5
Edit5: Added the Edit thingies
Edit: I mistyped >.<
Edit2:Sorry for edits
Edit:3+4
Why:
Edit6:(sqrt(2)+sqrt(3))^100= 60189565958534864248505242941893634932281257785715.1875721641483405
The units digit, is the number before the comma, thus being 5
Edit5: Added the Edit thingies
i think 3 as well o3o/
4
because 4 is cool
because 4 is cool
maybe 6
my brain melted
my brain melted
Tried to use calculators and WolframAlpha, but exponents and stuff... lol
And looks like this is becoming a guessing game!
no goddammit; let's try again.
let's try with 7 for now lol
sqrt(2) + sqrt(3) = 1.414213562373095 + 1.732050807568877 = 3.146264369941972
3.146264369941972 ^100 = 314.6264369941972
this is like how i was thaught maths on school i guess i dunno
oh wait i'm missing stuff
3.146264369941972 ^100 = 314
this is like how i was thaught maths on school i guess i dunno
oh wait i'm missing stuff
Uhm, ^ betekent Kwadraat, en niet KeerAyu wrote:
sqrt(2) + sqrt(3) = 1.414213562373095 + 1.732050807568877 = 3.146264369941972
3.146264369941972 ^100 = 314.6264369941972
this is like how i was thaught maths on school i guess i dunno
Maybe you'll know how to do it after reading this little example
3^3 is 3x3x3=27, not 3*3=9
borkbaraatje123 wrote:
Uhm, ^ betekent Kwadraat, en niet KeerAyu wrote:
sqrt(2) + sqrt(3) = 1.414213562373095 + 1.732050807568877 = 3.146264369941972
3.146264369941972 ^100 = 314.6264369941972
this is like how i was thaught maths on school i guess i dunno
Maybe you'll know how to do it after reading this little example
3^3 is 3x3x3=27, not 3*3=9
Topic Starter
come on guys it is not a random guessing quiz..
anyway, game three:
trying to find out which map the image i post comes from:
first one will win a modding ticket
anyway, game three:
trying to find out which map the image i post comes from:
first one will win a modding ticket
In that case it's 6
3.146264369941972^100 = 6.018956595853486424685058163435e+49
3.146264369941972^100 = 6.018956595853486424685058163435e+49
Ok my guess is: 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 or 0
Reason: it has to be one of them.
IT
HAS
TO.
Irre4mathking
http://osu.ppy.sh/s/17275 DystopiaGround - Silence, In the Rubble
Storyboard
Storyboard
Looks a little far fetchedOniJAM wrote:
17275
Topic Starter
good you got itOniJAM wrote:
http://osu.ppy.sh/s/17275 DystopiaGround - Silence, In the Rubble
Storyboard
it's (√2+ √3)^100 so we should find integer first
(√2+ √3)^8 is 9602. so (√2+ √3)^8 's digit is 2.
and 2^x 's digit goes 2, 4, 8, 6, 2, 4, 8, 6 .....
so (√2+ √3)^96 is 6.
and (√2+ √3)^4 is 97.9897....
(√2+ √3)^96 = 6
6[(√2+ √3)^96's digit] * 97. 9897[(√2+ √3)^4] goes 587, 8382....
so digit is 7
Answer : 7
(√2+ √3)^8 is 9602. so (√2+ √3)^8 's digit is 2.
and 2^x 's digit goes 2, 4, 8, 6, 2, 4, 8, 6 .....
so (√2+ √3)^96 is 6.
and (√2+ √3)^4 is 97.9897....
(√2+ √3)^96 = 6
6[(√2+ √3)^96's digit] * 97. 9897[(√2+ √3)^4] goes 587, 8382....
so digit is 7
Answer : 7
mathematica calculated
the answere is 8
the answere is 8
Are you allowed to round it to an integer? It should be 1 right I don't even math, kill me nowNeta wrote:
it's (√2+ √3)^100 so we should find integer first
(√2+ √3)^8 is 9602. so (√2+ √3)^8 's digit is 2.
Answer : 7
N[(Sqrt[2] + Sqrt[3])^100, 286] = 6.01896 × 10^49
6 i think
6 i think
hue I'm fool
60189565958534864246850581634349698760897425062497
ok I think neta wins
60189565958534864246850581634349698760897425062497
ok I think neta wins
I have no idea about this.
Maybe i'm wrong or not. it's too hard question
Maybe i'm wrong or not. it's too hard question