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Brain teaser game

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126
Topic Starter
Knarf
It is an interesting game :) Easy rules:

First, I will ask a brain teaser.
Then, someone who answered it correctly, after confirmed (or 24hrs without response while the answer is beyond dispute), can ask a brain teaser, and the cycle repeats.

A brain teaser that can be explained in non-specific languages is preferable. For example,
Q: Why does Tom run faster than a moving train?
A: Because he runs really fast.

Q: There are two monsters, green-faced and red-faced. Green-faced monster has to be killed with two shots while red-faced monster has to be killed with just one shot. How can I kill both monsters with two shots?
A: First, kill the green-faced moster with one shot. Then face of red-faced monster will turn green due to scary, so I can kill it with another shot.

:) Now comes the question:
Each can of Coke costs $1. There is a discount that you can exchange a new can of Coke with two empty can. You now have $20. How many cans of Coke can you drink?

Edit: add rule (24hrs without response)
nrl
39
Topic Starter
Knarf
No 39 :D Think further
boat

kookookook wrote:

How many cans of Coke can you drink?
As many as your stomach allows for.

Now where is my prize?
Topic Starter
Knarf

boat wrote:

kookookook wrote:

How many cans of Coke can you drink?
As many as your stomach allows for.

Now where is my prize?

Okay... the question now is how many cans can you buy/exchange :(
nrl
39, with a remainder of 1 empty can.
Topic Starter
Knarf
Consider the remaining can ;)
nrl
Well, there are only 39 cans total.
Topic Starter
Knarf
Don't you think it is a little bit waste when remaining one empty can... What can you do with such can?
mathexpert
40?
nrl
Kick it? If you can refill the cans then the answer is infinity.
Topic Starter
Knarf

mathexpert9981 wrote:

40?
Yes it is 40
Please explain and it's your turn :)
Jinxy
Like what, you share a can with another guy? 39.5?

Then you find 2 more guys and share a can between 4 people, 39.75

This goes on to infinity and the end result is 40 like what mathexpert said
mathexpert
lol it's much more simple than that dude

Inital: 20 cans
20 + 10+ 5 + 2 +1 = 39;
but, there was an extra can from the 5 -> 2. Adding this can with the last +1 would mean 2 empty cans. thus, the real answer is 40.


nvm;

20 + = 40

I'll post mine soon~
nrl

mathexpert9981 wrote:

20 + 10+ 5 + 2 +1 = 39;
38, not 39.
Topic Starter
Knarf
Let me explain :)
you will get
20+10+5+2(1 empty can)+1(1 empty can)+1=39
For the remaining empty can, ask someone to lend you an empty can, then exchange a new can, and after drinking, give it back to him/her.
So the answer is 40. :D
mathexpert
Somebody can take my turn, I don't really have any good logic puzzles; the ones I do have involve too much math as opposed to logic stuff~
nrl
But whoever gave you the can would essentially be giving up half a drink. Why would they do that? :P

mathexpert9981 wrote:

Somebody can take my turn, I don't really have any good logic puzzles; the ones I do have involve too much math as opposed to logic stuff~
Pass.
MiharuUwU
i would have just purchased a bunch of recycled cans and exchange them in turn bankrupting the coke business or causing them to rethink their promotions
Topic Starter
Knarf
Let me ask again :)
A man and a woman dated in a restaurant.
The man asked,' How old are you?'
The woman said nothing but got a piece of lemon from her lemon tea and put it on the table in front of the man.
How old was she?

Edit:Sorry for my poor English :) Thanks miharu
Topic Starter
Knarf

mathexpert9981 wrote:

lol it's much more simple than that dude

Inital: 20 cans
20 + 10+ 5 + 2 +1 = 39;
but, there was an extra can from the 5 -> 2. Adding this can with the last +1 would mean 2 empty cans. thus, the real answer is 40.


nvm;

20 + = 40

I'll post mine soon~

I prefer this one :)
nrl
Neither of those works in the context of this problem.
Topic Starter
Knarf

NarrillNezzurh wrote:

Neither of those works in the context of this problem.
yum :D
MiharuUwU
what does this even mean?

kookookook wrote:

The woman said nothing but fished up a piece of lemon in front of the man.
Topic Starter
Knarf
Sorry for my poor English. Oh I forgot to tell the main point :?
I would like to express that the woman get a piece of lemon from her lemon tea and put it on the table in front of the man.
MiharuUwU
10?
also how old was her should be changed to how old was she ,english is confusing and redundant sometimes having all these words with the same or similar meanings
Senritsu
lol let me guess without thinking too much (?)
29 maybe? lol
Topic Starter
Knarf
Not 10
Not 29
Hint: LEMON :D
KinkiN
17?

source : google sensei. It's the amount of calories in 58gr lemon
Topic Starter
Knarf
You got one digit correct :)
But sorry, I think google cannot help answer this question.
KinkiN
okay it's 27.
Topic Starter
Knarf
Sorry not 27
LEMON <---you can see something here
Jinxy
37

LEMON inverted is (approx.) NOW37

pass.
Topic Starter
Knarf
Bingo :) your turn
I don't want to ask again, either. So anyone?
Jinxy
Meh, here's an easy one.

You need to roll a ball from Point A to Point B on a field without overshooting. The two points are 20m apart.
However, you can only roll it 2m, 3m, 5m, 7m, or 11m each time

What is the minimum number of rolls you need to use?
AmberLynx
1. I only have one ball :<
Jinxy
fixed
Topic Starter
Knarf
Take Move Point B as to Point A. They overlap so 0 rolls :D
AmberLynx
If I only have one ball and can only roll it to a maximum distance of 11m each time then I'll never reach point B. So 0.
Topic Starter
Knarf

salted_nuts wrote:

If I only have one ball and can only roll it to a maximum distance of 11m each time then I'll never reach point B
I think he means 11+11-2 or 11+2+7
Jinxy

kookookook wrote:

Take Move Point B as to Point A. They overlap so 0 rolls :D
Fixed points on the field

kookookook wrote:

salted_nuts wrote:

If I only have one ball and can only roll it to a maximum distance of 11m each time then I'll never reach point B
I think he means 11+11-2 or 11+2+7
In a way, like that. You can roll 1 ball multiple times.
AmberLynx
oh ._. then 3
Topic Starter
Knarf
So I ask a question :D
I think of a tough question. I even wonder if I am wrong, so I share here.
There are three coins, one with both sides silver, one with both sides gold, and one with one side silver and one side gold.

I randomly choose one coin, and it is given that the face of the coin I see is gold.
What is the probability that the other side of the coin is gold too?
Jinxy
Hold your horses, 3 is wrong. The answer is pretty obvious now, so the key is to explain it.
NoHitter
50% is the obvious answer, but I feel like it's not that.

Edit:
Also JInxy, it's two.
Roll it twice 11 times then just stop the ball as you reach 20.
Topic Starter
Knarf
I am thinking of 1/3, but I seem haven't answer JInxyjem's question correctly yet :)

Edit:

NoHitter wrote:

50% is the obvious answer, but I feel like it's not that.

Edit:
Also JInxy, it's two.
Roll it twice 11 times then just stop the ball as you reach 20.
Oh I arrive the answer now. It is two. I roll two times 11 with different angles, so the vector sum is 20.
Jinxy
Yeah, the points are on a field, so you can roll in any direction.
NoHitter

kookookook wrote:

Oh I arrive the answer now. It is two. I roll two times 11 with different angles, so the vector sum is 20.
Oh dear how could I have forgotten to think in three dimensions.
Still, I think my answer is acceptable to some degree xD
NoHitter

kookookook wrote:

So I ask a question :D
I think of a tough question. I even wonder if I am wrong, so I share here.
There are three coins, one with both sides silver, one with both sides gold, and one with one side silver and one side gold.

I randomly choose one coin, and it is given that the face of the coin I see is gold.
What is the probability that the other side of the coin is gold too?

kookookook wrote:

I am thinking of 1/3, but I seem haven't answer JInxyjem's question correctly yet :)
Isn't it 50%? The moment you see the coin is gold, it's either gold coin or gold-silver coin already.

Edit: Nevermind. Looks like Monty Hall's has tricked me again.
Your question is a variety of the Monty Hall's problem. The answer is 2/3.
Topic Starter
Knarf

NoHitter wrote:

kookookook wrote:

So I ask a question :D
I think of a tough question. I even wonder if I am wrong, so I share here.
There are three coins, one with both sides silver, one with both sides gold, and one with one side silver and one side gold.

I randomly choose one coin, and it is given that the face of the coin I see is gold.
What is the probability that the other side of the coin is gold too?

kookookook wrote:

I am thinking of 1/3, but I seem haven't answer JInxyjem's question correctly yet :)
Isn't it 50%? The moment you see the coin is gold, it's either gold coin or gold-silver coin already.
I think the probability of choosing a both-side-gold coin is different from that of one-side-gold-one-side-silver coin.
_____________________________Face________Face
both-side-gold_________________ Gold_______ Gold
one-side-gold-one-side-silver______Gold________Silver
both-side-silver_________________Silver________Silver

Obviously the chance of getting a both-side-gold is 2/3 and chance of getting a one-side-gold-one-side-silver coin is 1/3.

Sorry I forgot the figure. Yes, it is 2/3
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