Oh wait.
Well, thats kinda backwards...
let x = 5;If you do the above, x will start at 0, but it will be set to the value of i, which is 0. As the loop continues, x will be set to 1, 2, 3, and eventually, 7. After it is set to 7, the local variable i is set to 8, and the loop ends, leaving x as 7. In total, the code loops 8 times, and i has values from 0 to 7.
ascent(i in 0..8){
x=i;
}
Well, thats kinda backwards...