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Probability

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Topic Starter
Meah
Probability of an Event

It is the measure of the chance that the event will occur as a result of an experiment.

Formula:

P(Event)= (Number of favorable outcome to an Event E)/(Total number of Possible Outcomes)

Problem:

Blitzfrog has returned and posted in 5 threads within 5 minutes. What is the probability of Blitzfrog getting silenced again?

Solution:

P(Event)= (Number of favorable outcome to an Event E)/(Total number of Possible Outcomes)
P(Blitzfrog's Silence) = 1 favorable outcome (getting silenced) / 1 possible outcome (getting silenced)
P(Blitzfrog's Silence) = 1/1

Therefore the probability of Blitzfrog getting silenced is 1/1, actually these are all random and the details above doesn't matter because it's common sense that Blitz's gonna get a silencehammer again soon! :D

peace frog!
Blitzfrog
-___-
Where is your faith??
+______________+
Topic Starter
Meah

Blitzfrog wrote:

-___-
Where is your faith??
+______________+
Gone with the wind
Blitzfrog

Meah wrote:

peace frog!
I wanna drop a nuclear bomb on top of you
DJ Enetro

Blitzfrog wrote:

I wanna drop a nuclear bomb on top of you


ME TOO, BLITZ HAS BEEN SILENCED TOO MUCH AND TOO LONG
Topic Starter
Meah

Blitzfrog wrote:

Meah wrote:

peace frog!
I wanna drop a nuclear bomb on top of you
Drop me daddy
Fhaye
Biased to begin with
There should be atleast 2 outcomes, getting silenced or getting away without silence
kai99
given that blitz is silenced what is the probability that bliz had spammed forums
Topic Starter
Meah

kai99 wrote:

given that blitz is silenced what is the probability that bliz had spammed forums
100
Topic Starter
Meah
Blitzfrog got silenced!
I am rite!
Luqanted
lmao wtf why was he silenced
kai99
rip
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