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Scorpiour's Modding Queue (Modding Team)

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IamKwaN
8
gxytcgxytc
错了/.\
wcx19911123
3
Kayano
(sqrt(2)+sqrt(3))^2=9.898979...
(sqrt(2)+sqrt(3))^4=97.989795...(8)
(sqrt(2)+sqrt(3))^8=9601.999896...
(sqrt(2)+sqrt(3))^16=92198401.999999989..
(sqrt(2)+sqrt(3))^32<...4
(sqrt(2)+sqrt(3))^64<...6
so (sqrt(2)+sqrt(3))^100<(sqrt(2)+sqrt(3))^64*(sqrt(2)+sqrt(3))^32*(sqrt(2)+sqrt(3))^4=………………8*4*6=2
so the unit digit is 1
keeeeeeko
Maybe 6?
sjoy
3
cheesiest
3
Ayu
314
DenoisoGoiso
101


lol random guessing
gxytcgxytc
再试试= =
原式=(√2+√3)^100-(2-√3)^100整数部分等于(√2+√3+√2-√3)^50 (√2+√3-√2+√3)^50
8^25*12^25
8^25 个位是8
2^25 个位2
结果6
Bara-
5

Edit: I mistyped >.<
Edit2:Sorry for edits

Edit:3+4
Why:
Edit6:(sqrt(2)+sqrt(3))^100= 60189565958534864248505242941893634932281257785715.1875721641483405
The units digit, is the number before the comma, thus being 5
Edit5: Added the Edit thingies :D
Suimya
i think 3 as well o3o/
Hard
8!
Nwolf
4

because 4 is cool
Xinely
maybe 6

my brain melted
Hinsvar
1.

Tried to use calculators and WolframAlpha, but exponents and stuff... lol

And looks like this is becoming a guessing game!


Hard to explain, but after actually calculating and analyzing a little more, it's most likely 8.

no goddammit; let's try again.
-kevincela-
let's try with 7 for now lol
Ayu
sqrt(2) + sqrt(3) = 1.414213562373095 + 1.732050807568877 = 3.146264369941972
3.146264369941972 ^100 = 314.6264369941972

this is like how i was thaught maths on school i guess i dunno

oh wait i'm missing stuff
Bara-

Ayu wrote:

sqrt(2) + sqrt(3) = 1.414213562373095 + 1.732050807568877 = 3.146264369941972
3.146264369941972 ^100 = 314.6264369941972

this is like how i was thaught maths on school i guess i dunno
Uhm, ^ betekent Kwadraat, en niet Keer
Maybe you'll know how to do it after reading this little example
3^3 is 3x3x3=27, not 3*3=9
Ayu

baraatje123 wrote:

Ayu wrote:

sqrt(2) + sqrt(3) = 1.414213562373095 + 1.732050807568877 = 3.146264369941972
3.146264369941972 ^100 = 314.6264369941972

this is like how i was thaught maths on school i guess i dunno
Uhm, ^ betekent Kwadraat, en niet Keer
Maybe you'll know how to do it after reading this little example
3^3 is 3x3x3=27, not 3*3=9
bork
Topic Starter
Scorpiour
come on guys it is not a random guessing quiz..

anyway, game three:

trying to find out which map the image i post comes from:

first one will win a modding ticket

Ayu
In that case it's 6

3.146264369941972^100 = 6.018956595853486424685058163435e+49
Irreversible
未来 都市 壁紙

Ok my guess is: 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 or 0

Reason: it has to be one of them.
IT
HAS
TO.

Irre4mathking
Kayano
http://osu.ppy.sh/s/17275 DystopiaGround - Silence, In the Rubble
Storyboard
Ayu

OniJAM wrote:

17275
Looks a little far fetched
Topic Starter
Scorpiour

OniJAM wrote:

http://osu.ppy.sh/s/17275 DystopiaGround - Silence, In the Rubble
Storyboard
good you got it
Neta
it's (√2+ √3)^100 so we should find integer first

(√2+ √3)^8 is 9602. so (√2+ √3)^8 's digit is 2.

and 2^x 's digit goes 2, 4, 8, 6, 2, 4, 8, 6 .....

so (√2+ √3)^96 is 6.

and (√2+ √3)^4 is 97.9897....

(√2+ √3)^96 = 6

6[(√2+ √3)^96's digit] * 97. 9897[(√2+ √3)^4] goes 587, 8382....

so digit is 7

Answer : 7
Koiyuki
mathematica calculated
the answere is 8
Ozato Fumika
6
pkk

Neta wrote:

it's (√2+ √3)^100 so we should find integer first

(√2+ √3)^8 is 9602. so (√2+ √3)^8 's digit is 2.


Answer : 7
Are you allowed to round it to an integer? It should be 1 right I don't even math, kill me now
blackabyss
N[(Sqrt[2] + Sqrt[3])^100, 286] = 6.01896 × 10^49
6 i think
Koiyuki
hue I'm fool
60189565958534864246850581634349698760897425062497
ok I think neta wins
Neta
I have no idea about this.

Maybe i'm wrong or not. it's too hard question
Topic Starter
Scorpiour
ok next game~~

Trying to find out which maps the following three screenshots comes from!

each one may post only once, and no edit allowed!

the first one whose post is completely correct will win a ticket!

for pattern case, you must post DIFF link or MAP link with Correct Diff Name





Topic Starter
Scorpiour

Neta wrote:

it's (√2+ √3)^100 so we should find integer first

(√2+ √3)^8 is 9602. so (√2+ √3)^8 's digit is 2.

and 2^x 's digit goes 2, 4, 8, 6, 2, 4, 8, 6 .....

so (√2+ √3)^96 is 6.

and (√2+ √3)^4 is 97.9897....

(√2+ √3)^96 = 6

6[(√2+ √3)^96's digit] * 97. 9897[(√2+ √3)^4] goes 587, 8382....

so digit is 7

Answer : 7
not the best way but pretty close so answer accept
gxytcgxytc
Avena
https://osu.ppy.sh/s/84014
First one, Extreme diff.

https://osu.ppy.sh/s/53451
Second one, Storyboard.

https://osu.ppy.sh/b/54581
Third one, Insane diff.
Topic Starter
Scorpiour

Priti wrote:

https://osu.ppy.sh/s/84014
First one, Extreme diff.

https://osu.ppy.sh/s/53451
Second one, Storyboard.

https://osu.ppy.sh/b/54581
Third one, Insane diff.

that it is
Neta
here's some fix about solution.

(√2+ √3)^8 is not integer i got rounding off to the nearest integer
Frostings

Neta wrote:

here's some fix about solution.

(√2+ √3)^8 is not integer i got rounding off to the nearest integer
if you don't round you get a completely different answer but the unit digit is still 7 I think
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