For when real math is too hard
Try to think of your own
ie.
X^2-2x-3=0
-2x^3=3
-2x=1
+-2, x=3 or -1
Try to think of your own
ie.
X^2-2x-3=0
-2x^3=3
-2x=1
+-2, x=3 or -1
forum
Imaginary Math
posted
Total Posts
22
I care
Topic Starter
Blitzfrog wrote:
Imaginary maths???
i didn't know this stuff exists
I didn't know math exists
Alright here an interesting one:
Suppose there is a 2D coordinate system where there are values from f(-infinity) to f(+infinity) and values from h(-infinity) to h(+infinity) where f(h(0)=h(f(0)).
The addition of such values is defined as such:
f(x) + f(x) = 2f(x)
h(x) + h(x) = 2h(x)
f(x) + h(x) = sqrt(f(x)^2 + h(x)^2)
The subtraction of such values is defined as such:
f(x) - f(x) = 0
h(x) - h(x) = 0
f(x) - h(x) = sqrt(f(x)^2 - h(x)^2)
h(x) - f(x) = sqrt(h(x)^2 - f(x)^2)
What is the distance between p1 = (f(2),h(4)) and p2 = (h(8), h(2)) in a Cartesian coordinate system?
Suppose there is a 2D coordinate system where there are values from f(-infinity) to f(+infinity) and values from h(-infinity) to h(+infinity) where f(h(0)=h(f(0)).
The addition of such values is defined as such:
f(x) + f(x) = 2f(x)
h(x) + h(x) = 2h(x)
f(x) + h(x) = sqrt(f(x)^2 + h(x)^2)
The subtraction of such values is defined as such:
f(x) - f(x) = 0
h(x) - h(x) = 0
f(x) - h(x) = sqrt(f(x)^2 - h(x)^2)
h(x) - f(x) = sqrt(h(x)^2 - f(x)^2)
What is the distance between p1 = (f(2),h(4)) and p2 = (h(8), h(2)) in a Cartesian coordinate system?
whoaabraker wrote:
Alright here an interesting one:
Suppose there is a 2D coordinate system where there are values from f(-infinity) to f(+infinity) and values from h(-infinity) to h(+infinity) where f(h(0)=h(f(0)).
The addition of such values is defined as such:
f(x) + f(x) = 2f(x)
h(x) + h(x) = 2h(x)
f(x) + h(x) = sqrt(f(x)^2 + h(x)^2)
The subtraction of such values is defined as such:
f(x) - f(x) = 0
h(x) - h(x) = 0
f(x) - h(x) = sqrt(f(x)^2 - h(x)^2)
h(x) - f(x) = sqrt(h(x)^2 - f(x)^2)
What is the distance between p1 = (f(2),h(4)) and p2 = (h(8), h(2)) in a Cartesian coordinate system?
Luqanted wrote:
1+2=4
-10^(1/2)
Topic Starter
How about half an a press
https://youtu.be/kpk2tdsPh0A
https://youtu.be/kpk2tdsPh0A
the integral sec y dy from 0 to one sixth of pi is log to base e of the square root of three times the 64th power of WHAT?
Topic Starter
DJ Enetro wrote:
the integral sec y dy from 0 to one sixth of pi is log to base e of the square root of three times the 64th power of WHAT?
Magic
1+1 =3
How would you like me to execute you?Stanvord wrote:
X^2-2x-3=0
-2x^3=3
-2x=1
+-2, x=3 or -1
Topic Starter
Kisses wrote:
Stanvord wrote:
X^2-2x-3=0
-2x^3=3
-2x=1
+-2, x=3 or -1
How would you like me to execute you?
Windows.exe is no longer responding~
[Force Quit] [Check For Solution]
[Check For Solution]Stanvord wrote:
Windows.exe is no longer responding~Kisses wrote:
How would you like me to execute you?
[Force Quit] [Check For Solution]
now go do something productive with your life
Topic Starter
[Check For Solution]Stanvord wrote:
Windows.exe is no longer responding~Kisses wrote:
How would you like me to execute you?
[Force Quit] [Check For Solution]
I don't have anything productiveabraker wrote:
now go do something productive with your life
cos (theta) + i sin (theta) = cis (theta)
r^n(cos(ntheta)+isin(ntheta)
r^n(cos(ntheta)+isin(ntheta)