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OT Bingo 2 [OVER; Winner: Meah]
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Send nudes for tile revealslevesterz wrote:
but is tuck at 19 point now ><
Noots is not nudeslevesterz wrote:
sentBlitzfrog wrote:
Send nudes for tile reveals
Try again
i cant win anyway lol ... i am just curious what that last tile of the slot is *i got two line that stuck at that last box*
tru truBlitzfrog wrote:
It's not about winning,
It's about points
Mea Mea
TRAP TRAP TRAP TRAP TRAP TRAP TRAP TRAPjohnmedina999 wrote:
Mea Mea
Blitzfrog wrote:
TRAP TRAP TRAP TRAP TRAP TRAP TRAP
Topic Starter
John, you were away for too long. We were finished with this a week agojohnmedina999 wrote:
Blitzfrog wrote:
TRAP TRAP TRAP TRAP TRAP TRAP TRAP
What happened?
Also, do I get the "bring up old meme/taboo topic" box?
Also, do I get the "bring up old meme/taboo topic" box?
Lots of stuff happenedjohnmedina999 wrote:
What happened?
Also, do I get the "bring up old meme/taboo topic" box?
Invisible trapMeah wrote:
Im no trap frog, Im legit John Cena 101%
We call them land mines
Topic Starter
U P D A T E
P
D
A
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E
P
D
A
T
E
oh wow, I see how this works
Topic Starter
This math is flawed. Given 17 unlocked tiles and 36 tiles total, any 12 positions which any of the 6 of the 17 tiles can be in if the game is won, and 11 positions where 11 of the 17 tiles cannot be in if the game is won:Blitzfrog wrote:
Well considering that there is 36 tiles
The total outcome is 36!/(36-19)!
=36!/17!
=1.0458433e+27
And that is a huge number
Considering also that the only possible way he/she I'm still not sure about micro-dick's gender gets a bingo is reaching 6 in a row horizontally or vertically. We can do an estimation of the possible bingo hits.
We know for sure he/she(it) has at least got 1 row/column. We can conclude that there is only 30 tiles available for randomisation. Consider also that this will be an over estimation due to the fact that you can't get bingos in multiple columns/multiple rows as the game would have ended. (note it is possible to get a row and a column). So we can conclude that the number of ways you can sort the 13 tiles in the 30 available tile space is
30!/(30-13)!
=30!/17!
=7.4574708e+17
Now note that 1.0458433e+27 is a much much larger number than 7.4574708e+17
Hence it is unlikely he/she would have got a bingo
Let Tile[x] be Tile 1 to 17.
Tile[1.. 6] = 6 tiles
Tile[7.. 12] = 6 tiles
Tile[13.. 17] = 5 tiles
Therefore at most, two positions of six are possible ignoring winning.
Suppose the game is won. Then there is one position where there are 6 tiles in a row.
Let Tile[1.. 6] by the tiles in the position.
Therefore the number of tiles there are free to for others to be placed on are:
NUM_TOTAL_TILES - NUM_WINNING_TILES - NUM_IMPOSSIBLE_TILES = 36 - 6 - 11, where
(NUM_TILES_NEEDED_TO_WIN - MAX_TILES_THERE_CAN_BE_WITHOUT_WIN) * NUM_IMPOSSIBLE_POSITIONS = (6 - 5) * 11 = 11
Which gives us 19 possible places where the remaining 11 tiles can be. 19 choose 11 = 75,582 possible combinations if win
Now in the instance the game is not won, there are 12 locations the 17 tiles cannot be in
The total number of position the tiles can be in ignoring that is 36 chose 17. Factoring in the 12 impossible locations, we get (36-12) choose 17 = 346,104 positions the tiles can be in if not win
To get the odds of win:
Win combinations/ (Win combinations + not win combinations) = 75,582/(75,582 + 346,104) = 17.92%
To get the odds of not win:
Not win combinations/ (Win com - fuck it just subtract from 100% you math illiterate fag.
Well I hope you learned something. I will now go while in fear I left a mistake somewhere. Have fun!
Fuck what did I miss.
Don't answer, it's probably best if I didn't know.
Don't answer, it's probably best if I didn't know.
Abraker I'll check our math when I get home but I somehow feel like that is not right
i take IB HL Maths and it's a nightmare but i still suck at math.
wtf
is the bingo becoming a math debate?
wtf
is the bingo becoming a math debate?
Ok here we go
Binomial Distribution incoming
Before we start here is the quote
Which equates to
0.16715542522
They exchange ideas
And body
And nudes
Abraker I was gonna graph this but I got lazy, can you graph it thx
Binomial Distribution incoming
Before we start here is the quote
By this quote I am assuming he means that the Bingo could have occured anytime and playing till 19 boxesRaging Bull wrote:
tbh im more impressed how kai has 19 boxes but no bingo
Which equates to
0.16715542522
No, mathematicians don't debatekai99 wrote:
i take IB HL Maths and it's a nightmare but i still suck at math.
wtf
is the bingo becoming a math debate?
They exchange ideas
And body
And nudes
Abraker I was gonna graph this but I got lazy, can you graph it thx
Blitzfrog wrote:
I hope you know binomial distribution abraker
why do i not have a fucking bingo yet am i defying all odds?
i still have tons of blank spaces
i still have tons of blank spaces
I screwed up
What I was calculating was the chance for bingo to hit on the 19th call
I need to add the sum of these from 1~19
What I was calculating was the chance for bingo to hit on the 19th call
I need to add the sum of these from 1~19
I wrote it in latex form doeRailey2 wrote:
i want to take a look at this
but
guys pls
I could join in this "exchange of ideas" but my brain is just rejecting math since break started
so, .. ... why do i not have a bingo yet?
kai99 wrote:
so, .. ... why do i not have a bingo yet?
Because the game is over, I won.
._.
Solve this for your probabilitykai99 wrote:
so, .. ... why do i not have a bingo yet?
Topic Starter
30 choose 13 is all possible arrangements given a win. Ok.Blitzfrog wrote:
Blitzmeth
Still wrapping my head around the multiplication by 12. A potential error in my method is that my math is a solution for where there are 6 tiles in one constant position for any possible win cases.
The following made realize a definite mistake I let happen:
Now that I think about it, it's a bit more complicated than that. You need to subtract 36 choose 19 by the number of scenarios prohibited due to a 2nd and 3rd six in a row.
Depending on what you're trying to calculate though. The multiplying by 12 is constant through out because there are only 12 ways you can win given any arrangement. But there are also the fact that there isn't only 12 ways to win with 19 tiles as the remaining 19-6 =13 tiles can be placed anywhere. That's why I multiplied the 12 with the fraction, not that you wouldn't know.
Only at school, hence school math since school is mental abuse to humanMeah wrote:
fuck math, mental abuse to humans